ANSWER QUESTION 1 AND 3 ONLY
^ means raise to power. i : means
that under i , u will get 1 , 2 , 3 , 4 , 5 . .
=============================PHYSICS PRACTICAL======
(1 )
Tabulate
i = L (cm )| |t 1( s )| |t1 (s )| | mean t( s )| | t( t/10 ) s | |logt (s )| | log
Lcm| |Log T * 10 ^ - 2 |( s )| | Log L * 10 ^ - 2 (cm )
1= | 80 . 00 | |17 . 87 | |17 . 56 | |17 . 715|
|17 . 715| | 0. 2483 | |1 . 9031| |24 . 83 |
|19 . 031|
2= | 7000 1622 1646 16340 16340 02133 18457 2133
18451
3= | 6000 1609 1509 15590 15590 01928 17782 1928
17782
4= | 5000 1408 1477 14425 14425 01591 16990
5= | 4000 1328 1336 13320 13320 01212
1591 16990 1212 16021
slope (s ) Log T 2 * 10 ^ - 2 /Log T 2 * 10 ^ - 1 - Log T 2 * 10 ^ - 2 /
Log T 2 * 10 ^ - 1 = (21 . 33 - 12 . 12 ( s ))* 10 ^ - 2 /
(18 . 50 - 16 . 02 ( cm )* 10 ^ - 1 )
=3 . 714* 10 ^ - 1
=0 . 3714cm ^ - 1
1axi )
i ) ensured supports of pendula were rigged
ii) avoided parallax error on meter rule / stop watch
1bi)
simple harmonic motion is the motion of a body whose
acceleration is always direct towards a fixed point and is
proportional to the displacement from the fixed points
1bii )
T =1 . 2 secs
Log 1 . 2 = 0. 079
0079 shown on graph with corresponding Log L read L
correctly determined
================================
TABULATE
x ( cm ) : 10 , 20 , 30 , 40 , 50 , 60
V (v ) : 0. 65 , 0 . 75 , 1 . 00 , 1 . 20 , 1. 45 , 1. 55
I ( A) : 0 . 20 , 0 . 30 , 0 . 35 , 0. 40 , 0 . 45 , 0 . 55
LogV (v ) : - 0 . 187, - 0 . 125, 0. 000, 0 . 079, 0 . 161, 0. 190
LogI ( ohm ) : - 0 . 699, - 0 . 523, - 0 . 456, - 0 . 396, - 0 . 391, - 0 . 360
SLOPE ( s ) : = ( LogI 2 - LOgI1 ) / (LogV 2 - LogV 1 )
=- 0 . 2 - ( - 0 . 7) /0 . 3 - (- 0. 2)
=0 . 5/ 0. 5
=1 AV ^ - 1
the emf of the battery is = 3 . 0v
3axi )
i ) ensured clean / tight terminals
ii) open key when reading was taken
3bi)
i ) brightness of the bulb increases
ii) voltage /current through the bulb increases
3bii )
i ) diode
ii) transistor
=================================
COmpleted .
...........
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